Item GlossaryEverQuest icon

Globe of Darkness [Shines darkness]  
 

Lore Item No Trade Placeable
Slot: RANGE
This item is placeable in yards, guild yards, houses and guild halls.
STA: +7
SV DISEASE: +15
WT: 0.0 Size: TINY
Class: ALL
Race: ALL
Slot 1, Type 7 (General: Group)

Item Lore:Shines darkness
Item Type:Misc
Stackable:No
Lucy Entry By:unknown
Item Updated By:SwiftyMUSE
Source:Live
IC Last Updated:2021-07-27 03:37:50
Page Updated:Thu Oct 9th, 2008

Expansion: Scars of Velious Scars of Velious


Rarity: Rare
Level to Attain: 55

[Quests | Recipes | Comments ]

This item is the result of a quest.
Expansion List - Premium only.
Quest Name
Deck of Spontaneous Generation

Crafted: This item is crafted by players.

Quests

This item is used in quests.
Expansion List - Premium only.

Plane of Mischief 1.0
Quest Name
The Gift Box

Used in 1 recipe.
Recipe list - Premium only.

Zone(s) Found In:


Zone Name
Plane of Mischief 2.0

Item Lore: Shines darkness
Screenshot

Uploaded November 27th, 2008
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Combine
# Jul 13 2013 at 6:14 PM Rating: Good
Sage
Avatar
**
277 posts
I can confirm that the following recipe is still used, as of July 2013, to create the Globe of Darkness on live servers (not Al'Kabor):

Black Crown
Black Throne
Blue Crown
Blue Throne
____________________________
quarken xired | tecknoe destructo
Mask of Tundra Walker
# May 21 2012 at 12:49 AM Rating: Decent
18 posts
I just did this combine on Al'Kabor the Mac server (Black Throne, Blue Throne, Black Crown, Blue Crown) and got a new item:
Mask of the Tundra Walker
AC 10 WIS 8
Illusion: Barbarian (Cast Time 7.0)
Class: Cleric
Race: HUM ERU
116280
# Feb 15 2004 at 1:16 PM Rating: Good
116280 possible combinations assuming you cant use the same card twice... there are 20 cards total, unless there are MORE that havent been found yet... these are the cards...

red Throne
red Crown
red Knight
red Squire
white Throne
white Crown
white Knight
white Squire
blue Throne
blue Crown
blue Knight
blue Squire
black Throne
black Crown
black Knight
black Squire
green Throne
green Crown
green Knight
green Squire

20 cards and you can only use 4 of them (4 slot container) so the formula would be 20x19x18x17 because you are removing the possibility of the same card being used twice
116,280 is a lot of combinations, some are definatly not going to work

hmmm, im wrong... forgot some minor detail (noticed when i was writing down all possible combinations) ill fix this when im done



Edited, Sun Feb 15 13:19:27 2004
RE: 116280
# May 13 2005 at 5:43 PM Rating: Decent
Quote:
assuming you cant use the same card twice


the cards are LORE- very safe assumption ~.^
RE: 116280
# Oct 31 2005 at 9:09 AM Rating: Decent
It's actually 20 chose 4 (don't know how to type it). Which is 20!/(4!(20-4)!) Which is 20x19x18x17/4 which is 29070, a fourth of what you said. 29070 is still pretty big though :)
Hmm?
# Jul 06 2001 at 8:08 AM Rating: Decent
Um, if there are 20 possible cards, and 4 slots to place them in, and nothing preventing you from using the same card type more than once, then the formula is 20x20x20x20 for possible combinations, giving you 160000. I'm not saying that you can use the same card more than once, but this would also mean that the problem becomes a bit easier if it does not matter what order the cards are in. If however is does matter, then if you must use one of each suit and there are five colors of each suit, then the possible combo for card one would be 5*4 then card two would be 5*3, card three 5*2 and card four 5. This total is 20*15*10*5=15000 combinations. At least this is what I figure. Just my 2cp
#REDACTED, Posted: Jul 06 2001 at 8:06 AM, Rating: Sub-Default, (Expand Post)
I'll give it a try
# Jun 12 2001 at 10:46 AM Rating: Default
There are 20 different cards soooooooo 20 choose 4 is <breaks out calculator> 4845.......... ok i'll go away now........
Let's just call it at this...
# Jun 11 2001 at 1:10 PM Rating: Default
There are FIVE different colored decks, and each has FOUR cards in it.

Now, you need ONE of each card, that is, crown, king, queen, jester (I forget just what, mebbe crown, king, jester, knight, servant, peasant.... whatever. 4 Cards to turn in.)

So, that means that we have four pools(One of each card) of 5 colors (in each pool) to choose from. There are 5 items in the first pool, 5 in the second, 5 in the third, and 5 in the fourth pool. It actually is 4^5. Yes? 4*4*4*4*4= What? 16*16*4, which in turn equals 16*64 which equals.... /em surrenders to pulling out pen and paper....

1024 combos. Follow-up on a theory I need to inspect coming next.
RE: Let's just call it at this...
# Oct 06 2002 at 1:33 PM Rating: Good
*
105 posts
There are 4 colors, 4 ranks.
You dont need one of each rank. (e.g. blue flower of functionality = all thrones)
you don't need one of each color (e.g buckler of doom is all the black cards.)
I'm aware order does not matter so there isnt 43680 ways to arrange the cards. It's a simple combination without replacement. 16c4 = 1820 possible combinations.

alternately, for people not familiar with combinations, here's another way to look at it...
For those who wish to simply multiply 16*15*14*13, remember that there are 24 ways to arrange 4 cards. your number will be 24 times too large. Therefore 43680/24 = 1820.
Permutations
# Jun 11 2001 at 11:56 AM Rating: Decent
Okay.. had to post.. the difference bewteen a combination and a permuation is that order doesn't matter in a combination, it does in a permutation. Since hand-ins aren't dependant on which card goes in which of the slots in the trade window, we are looking for combinations. Those pad locks on your gym locker aren't combination locks, they are permuation locks. The first number you enter must be the first number. What's all that boil down to? There aren't 1024 differnent solutions. Just 120. Just. O:)
#Anonymous, Posted: Jun 11 2001 at 6:41 AM, Rating: Sub-Default, (Expand Post) ummmm 2+2=4 :)
sumdumgoi
# Jun 09 2001 at 10:36 AM Rating: Default
If you click the link above you'll see this is one of 18 rewards currently listed for this quest......well......here just read WoW by Nosferatu...
...Think about this though, before putting down the "cards" in the game.

SO far thats 18!! different items found so far. Now there should be 5 colors (and 4 types of cards): Green - poison, black - disease, red - fire, blue - ice, white - magic (all 5 resists).

So, if my memory of my math classes (phew..been WAY too long)..it would be 4 to the n (or 4 to the 5th power). That means 4 x 4 x 4 x 4 x 4 which equals, 1024 possible combinations. Unfortunately, it includes duplicate combinations. I know the formula is wrong, but I can't remember the proper one. I want to say it's C(5,4) but damned if I remember how to compute that formula.

Any math majors around?......guy who posted this just screwed up slightly)
RE: sumdumgoi
# Jun 10 2001 at 10:54 AM Rating: Decent
Actually, it's much worse than you think.

If you count the cards listed in the current 18 combinations, you see that there are
4 colors and 4 card types (White Crown isn't listed, but I assume it exists). This means
that you have 16 different cards, from which you must choose 4. The correct formula
for computing the number of possible rewards would be C(16,4). The formula for
computing combinations is C(n,r) = n!/(n-r)!*r! , and gives you 16!/(16-4)!*4! = 1820.
This means that there are 1820 unique ways to turn four cards. I seriously doubt that
the dev team has added 1820 new items for just one quest. This means there will be
MANY MANY MANY combinations which fail to provide a reward.
RE: sumdumgoi
# Jun 09 2001 at 2:30 PM Rating: Decent
C(5,4) = 5*4*3*2 if my memory is correct, which turns to be 120 possible combinations, much less than 1024.
RE: sumdumgoi
# Jun 09 2001 at 8:08 PM Rating: Decent
The correct way of expressing it is 5!, but yes, 120 is the correct answer.

It is not
C(n,r) = n!/(r!(n-r)!) is the combination formula.. if you do it as a combination.. it's (5!) / (4!)* (1!)

which simplifies to (5*4*3*2) / (4*3*2) * (1!).. Which simplifies to 120/24, which is 5, which is not the correct answer, obviously.

You were perhaps thinking of the permutation formula P(n,r) = n!/(n-r)! which is (5!) / (1!) which ultimately simplifies to 120, however this is not really necessary for this situation, and is more useful in a more complex situation.

I remember all this from highschool math, although I don't remember the actual practical use for combinations and permutations, I'm sure there is some practical use but I don't really feel like thinking about it now.. ! is really the only function that I've never found useful.
RE: sumdumgoi
# Jun 10 2001 at 11:38 AM Rating: Decent
The factorial function can be useful. N! tells you how many possible ways you can
arrange a line of N people. Factorial is about order of selection. Permutations cover
possible combinations, while considering the order in which they are selected.
Combinations do not care about order. As for practical uses, here are some:

Factorial (!):
You have a group of 6 people in Lower Guk, camping the FBSS. Since each person
wants one, you have decided to roll for it. You want to know how long it might take
for you to get one. Well, you need to know how many possible ways there are to
arrange a line of 6 people. The answer to this is 6! = 720. Of those 720, 120 times
you will be the first to receive the FBSS, but 120 other times you will be the LAST.

Combination C(n,r):
If you expect 2 FBSS to drop during the time you will be there, then what are your
chances of getting one of the three? C(6,2) tells you that there are 15 ways to
distribute the 2 FBSS. Since five of those combinations include you, your chances
of getting a FBSS are 5/15 = 1/3 (Yes. You could do 2/6, but that would be too easy)

Permutation P(n,r):
Here is where it gets interesting. Say you want to LEAVE as soon as you get your
FBSS. You want to know how many possible cases there are where you will get your
FBSS, and be either the first or second to get one of three FBSS you expect to drop.
You need to do P(6,3) = 120, then P(5,2) = 20. This means that 20 times you will get
the first FBSS, and 20 times you will get the second FBSS. So, 40/120 times you will
get either the first or second FBSS, giving you a 33% chance of being the first or
second person to abandon the camp with phat lewts.

So, um...there.
(If any math professors find this information to be incorrect, then please correct it. I
don't have my textbooks with me to verify it)
RE: sumdumgoi
# Apr 05 2004 at 3:30 PM Rating: Decent
too much math.. my head is about to expload :/
RE: sumdumgoi
# Jun 09 2001 at 9:54 PM Rating: Decent
Ouch! My Head hurts.
I seem to remember combinations and permutations being explained as a way to predict odds and, believe it or not, combinations. It was made to simplify more complex problems such as: 30 shirts, 20 pants, 10 pairs of shoes, and 3 belts will make how many individual outfits? While this particular example may not seem all that important, there are some people who find these equations and formulas great conveniences. I also had to remember this from high school, but unlike the poster above, I would not have remembered the equations so well without text book help =)
That would suck...
# Jun 08 2001 at 6:57 PM Rating: Default
I don't think we'll be seeing may of these, unless somebody accidentily turns in the wrong combo of items :p
RE: That would suck...
# Jun 09 2001 at 7:40 AM Rating: Default
Maybe so, but Verant is obviosuly pushing for more resist gear loot on alot of the more challenging Velious mobs. Maybe this is a hint towards the expansion, maybe not. Just something to think about.
RE: That would suck...
# Jun 09 2001 at 2:13 AM Rating: Default
Well, I must admit that it does suck....for now. When the Plane of Plague comes out....mgiht this be a more desirable item?
LOL
# Jun 08 2001 at 4:27 PM Rating: Default
Well I guess the person who got this one already made his/her own comment on the worth of this one.
RE: LOL
# Jun 09 2001 at 12:09 AM Rating: Default
no doubt...that's pretty funny :)
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